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Subject: Continuity and Differentiability
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    <TD vAlign=3Dtop>
      <H2><FONT color=3D#550000>Continuity &amp; Differentiability=20
      <BR><I>miscellaneous on-line topics for </I><BR><I><FONT=20
      color=3D#998800>Calculus Applied to the Real World</FONT></I> =
<BR>Part B:=20
      Differentiability=20
      <CENTER></CENTER></FONT></H2></TD>
    <TD>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; </TD>
    <TD><A =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/index.html"=20
      target=3D_top><FONT face=3D"arial, helvetica, sans-serif" =
color=3D#550000=20
      size=3D2><B>Return to Main Page</FONT></A> <BR><A=20
      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/conta=
nddiff.html"><FONT=20
      face=3D"arial, helvetica, sans-serif" color=3D#ff0000 =
size=3D2><B>Part A:=20
      Continuity</FONT></B></A> <BR><A=20
      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/candd=
ex.html"><FONT=20
      face=3D"arial, helvetica, sans-serif" color=3D#550000 =
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      This Topic</B></FONT></A> <BR><A=20
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<FONT=20
      face=3D"arial, helvetica, sans-serif" color=3D#550000 =
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      On-Line Topics</FONT></B></A> <BR><A=20
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href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/tccalcp.html"><F=
ONT=20
      face=3D"arial, helvetica, sans-serif" color=3D#009922 =
size=3D2><B>Everything for=20
      Calculus</B></FONT></A> <BR><A=20
      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/tcfinitep.html">=
<FONT=20
      face=3D"arial, helvetica, sans-serif" color=3Dcrimson =
size=3D2><B>Everything for=20
      Finite Math</B></FONT></A> <BR><A=20
      =
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      Finite Math &amp; Calculus</B></FONT></A> <BR><A=20
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tml"=20
      target=3D_blank><FONT face=3D"times, times new roman" =
color=3Dtomato><B>Utility:=20
      </B></FONT><FONT face=3D"arial, helvetica, sans-serif" =
color=3D#550000=20
      size=3D2><B>Function Evaluator &amp; Grapher</B></FONT></A>=20
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<P><B><FONT color=3D#ff0000 size=3D+1>Part B: =
Differentiability</FONT></B>=20
<P><B>Note </B>To understand this topic, you will need to be familiar =
with=20
derivatives and limits, as discussed in the chapter on the subject in =
<I><FONT=20
color=3D#aa00dd>Calculus Applied to the Real World.</FONT></I> If you =
like, you=20
can review the <A=20
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/Calcs=
ummary2.html">topic=20
summary material on derivatives and limits</A> or, for a more detailed =
study,=20
the <A=20
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/tutor=
ials/frames2_1.html">on-line=20
tutorials on derivatives and limits</A>.=20
<P>To begin, we recall the definition of the derivative of a function, =
and what=20
it means for a function to be differentiable.=20
<P>
<CENTER>
<TABLE width=3D"90%" bgColor=3D#eeeeff border=3D1>
  <TBODY>
  <TR>
    <TD><B><FONT color=3D#0000ff>Derivative; =
Differentiability</FONT></B>=20
      <BR>The <B>derivative</B> of the function f at the point a in its =
domain=20
      is given by=20
      <UL>
        <TABLE>
          <TBODY>
          <TR>
            <TD>f<FONT face=3DCourier>'</FONT>(a)</TD>
            <TD>=3D</TD>
            <TD align=3Dmiddle>lim<BR>h<IMG=20
              =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
            <TD vAlign=3Dtop>
              <CENTER>f(a+h) <FONT face=3DCourier>-</FONT> f(a)<BR><IMG =
height=3D1=20
              =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
              width=3D60><BR>h</CENTER></TD></TR></TBODY></TABLE></UL>
      <P>We say that function f is <B>differentiable at the point a in =
its=20
      domain</B> if f<FONT face=3DCourier>'</FONT>(a) exists.=20
      <P><B><FONT color=3D#0000ff>Differentiable on a Subset of the=20
      Domain</FONT></B> <BR>The function f is <B>differentiable on the =
subset S=20
      of its domain</B> if it differentiable at each point of S.=20
      <P><B><FONT color=3D#0000ff>Note</FONT></B>=20
      <TABLE>
        <TBODY>
        <TR>
          <TD>A function can fail to be differentiable at a point a if=20
          either</TD>
          <TD align=3Dmiddle>lim<BR>h<IMG=20
            =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
          <TD vAlign=3Dtop>
            <CENTER>f(a+h) <FONT face=3DCourier>-</FONT> f(a)<BR><IMG =
height=3D1=20
            =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
            width=3D60><BR>h</CENTER></TD>
          <TD>does not exist, or is =
infinite.</TD></TR></TBODY></TABLE>In the former=20
      case, we sometimes have a cusp on the graph, and in the latter =
case, we=20
      get a point of vertical tangency.=20
      <CENTER><IMG=20
      =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/pics3/=
pic3.gif"></CENTER>
      <P></P></TD></TR></TBODY></TABLE></CENTER>
<P> <BR><!************* BEGIN EXAMPLE ********************><SUB><IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/exiconw.gif"=
></SUB><FONT=20
color=3D#330033 size=3D4> <B>Example 1 </B><I>Functions Not =
Differentiable at=20
Isolated Points </I></FONT>
<P>Determine points of non-differentiability of the following =
functions</P>
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD><B>(a)</B></TD>
      <TD>f(x)</TD>
      <TD>=3D</TD>
      <TD>(x<FONT face=3DCourier>-</FONT>1)<SUP>1/3</SUP></TD>
      <TD>&nbsp; &nbsp;</TD>
      <TD><B>(b)</B></TD>
      <TD>g(x)</TD>
      <TD>=3D</TD>
      <TD>|x+2|</TD>
      <TD>&nbsp; &nbsp;</TD>
      <TD><B>(c)</B></TD>
      <TD>r(x)</TD>
      <TD>=3D</TD>
      <TD>
        <CENTER>x<SUP>2<BR><IMG height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D25><BR>x <FONT face=3DCourier>-</FONT>=20
  1</CENTER></SUP></TD></TR></TBODY></TABLE></UL>
<P></P>
<P><FONT color=3D#330033 size=3D4><B>Solution</B></FONT> </P><IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/pics3/=
pic4.gif"=20
align=3Dright>=20
<P><B>(a) </B>The power rule tells us that f(x) =3D (x<FONT=20
face=3DCourier>-</FONT>1)<SUP>1/3</SUP> has derivative f<FONT=20
face=3DCourier>'</FONT>(x) =3D (1/3)(x<FONT =
face=3DCourier>-</FONT>1)<SUP><FONT=20
face=3DCourier>-</FONT>2/3</SUP> everywhere where this expression is =
defined, and=20
is not diffeentiable when (1/3)(x<FONT =
face=3DCourier>-</FONT>1)<SUP><FONT=20
face=3DCourier>-</FONT>2/3</SUP> is not defined. Since (x<FONT=20
face=3DCourier>-</FONT>1) has a negative exponent, f<FONT =
face=3DCourier>'</FONT>(x)=20
is not defined when x =3D 1, and so f is not differentible there. In =
fact, direct=20
calculation shows that=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>f(1+h) <FONT face=3DCourier>-</FONT> f(1)<BR><IMG =
height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D60><BR>h</CENTER></TD>
      <TD>=3D</TD>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>h<SUP>1/3</SUP><BR><IMG height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D10><BR>h</CENTER></TD>
      <TD>=3D</TD>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>1<BR><IMG height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D10><BR>h<SUP>2/3</SUP></CENTER></TD>
      <TD>=3D</TD>
      <TD>+<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/gf/infty1.gif">,<=
/TD></TR></TBODY></TABLE></UL>showing=20
that f is not differentiable at x =3D 1.=20
<P><IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/pics3/=
pic5.gif"=20
align=3Dright>=20
<TABLE>
  <TBODY>
  <TR>
    <TD><B>(b)</B></TD>
    <TD>Since g(x) =3D |x+2| =3D </TD>
    <TD><IMG height=3D35=20
      =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/L=
B.GIF"=20
      width=3D4></TD>
    <TD><FONT face=3DCourier>-</FONT>(x+2) <BR>&nbsp;<BR>x+2 </TD>
    <TD>&nbsp; </TD>
    <TD>if x <IMG=20
      =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/gf/lte.gif"> =
<FONT=20
      face=3DCourier>-</FONT>2<BR>&nbsp;<BR>if x &gt; <FONT=20
    face=3DCourier>-</FONT>2</TD>
    <TD>&nbsp; ,</TD></TR></TBODY></TABLE>and since we know that both =
<FONT=20
face=3DCourier>-</FONT>(x+2) and x+2 are differentiable, the only point =
where=20
something can go wrong is when x =3D <FONT face=3DCourier>-</FONT>2. At =
this point,=20
we can compute the limit of the difference quotient directly:=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>f(<FONT face=3DCourier>-</FONT>2+h) <FONT =
face=3DCourier>-</FONT>=20
        f(<FONT face=3DCourier>-</FONT>2)<BR><IMG height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D75><BR>h</CENTER></TD>
      <TD>=3D</TD>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>|h|<BR><IMG height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D10><BR>h</CENTER></TD>
      <TD>.</TD></TR></TBODY></TABLE></UL>However, this limit does not =
exist (see=20
Example 2 in Section 6 of the chapter on derivatives in <I><FONT=20
color=3D#aa00dd>Calculus Applied to the Real World</FONT></I>) since the =
left- and=20
right limits differ. <IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/pics3/=
pic6.gif"=20
align=3Dright>=20
<P><B>(c) </B>The quotient rule tells us that r(x) =3D x<SUP>2</SUP>/(x =
<FONT=20
face=3DCourier>-</FONT> 1) is differentiable everywhere except at x =3D =
1. However,=20
x =3D 1 is not in the domain of r, and so r is differentiable at every =
point of=20
its domain.=20
<P>As we see in the graph on the right, there are no points of vertical =
tangency=20
or cusps.=20
<P><FONT color=3D#330033 size=3D4><B>Before We Go On...</B></FONT> =
</P>As you can=20
see, the graphs provide immediate information as to where to look for a =
point of=20
non-differentiability: a point where there appears to be a cusp or a =
vertical=20
tangent.=20
<P>
<HR>

<P><!**************** END EXAMPLE ********************>
<P>Here is one for you.=20
<P><!************* BEGIN EXAMPLE ********************><SUB><IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/exiconw.gif"=
></SUB><FONT=20
color=3D#330033 size=3D4> <B>Example 2 </B><I>Points of =
Non-Dfferentiability=20
</I></FONT>
<P>
<FORM name=3DtheForm1>
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD>
        <P><B><FONT color=3D#aa00dd size=3D+1>Q </FONT></B></P></TD>
      <TD>f(x) =3D (x<FONT face=3DCourier>-</FONT>1)<SUP>4/3</SUP> =
is</TD>
      <TD><SELECT name=3DCHOICE1> <OPTION selected>Select one<OPTION>not =

          =
differentiable<OPTION>differentiable<OPTION>undefined</OPTION></SELECT>=20
      </TD>
      <TD>at x =3D 1</TD>
      <TD><IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/smallblank.g=
if"=20
        name=3DpicQ1></TD>
      <TD><INPUT onclick=3Dcalc(1) type=3Dbutton value=3DCheck> =
</TD></TR>
    <TR>
      <TD>
        <P><B><FONT color=3D#aa00dd size=3D+1>Q </FONT></B></P></TD>
      <TD>f(x) =3D (x<FONT face=3DCourier>-</FONT>1)<SUP>2/3</SUP> =
is</TD>
      <TD><SELECT name=3DCHOICE2> <OPTION selected>Select one<OPTION>not =

          =
differentiable<OPTION>differentiable<OPTION>undefined</OPTION></SELECT>=20
      </TD>
      <TD>at x =3D 1</TD>
      <TD><IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/smallblank.g=
if"=20
        name=3DpicQ2></TD>
      <TD><INPUT onclick=3Dcalc(2) type=3Dbutton value=3DCheck> =
</TD></TR>
    <TR>
      <TD>
        <P><B><FONT color=3D#aa00dd size=3D+1>Q </FONT></B></P></TD>
      <TD>f(x) =3D (x<FONT face=3DCourier>-</FONT>1)<SUP><FONT=20
        face=3DCourier>-</FONT>1/3</SUP> is</TD>
      <TD><SELECT name=3DCHOICE3> <OPTION selected>Select one<OPTION>not =

          =
differentiable<OPTION>differentiable<OPTION>undefined</OPTION></SELECT>=20
      </TD>
      <TD>at x =3D 1</TD>
      <TD><IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/smallblank.g=
if"=20
        name=3DpicQ3></TD>
      <TD><INPUT onclick=3Dcalc(3) type=3Dbutton value=3DCheck> =
</TD></TR>
    <TR>
      <TD>
        <P><B><FONT color=3D#aa00dd size=3D+1>Q </FONT></B></P></TD>
      <TD>f(x) =3D |x<FONT face=3DCourier>-</FONT>1|<SUP>4/3</SUP> =
is</TD>
      <TD><SELECT name=3DCHOICE4> <OPTION selected>Select one<OPTION>not =

          =
differentiable<OPTION>differentiable<OPTION>undefined</OPTION></SELECT>=20
      </TD>
      <TD>at x =3D 1</TD>
      <TD><IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/smallblank.g=
if"=20
        name=3DpicQ4></TD>
      <TD><INPUT onclick=3Dcalc(4) type=3Dbutton value=3DCheck>=20
</TD></TR></TBODY></TABLE></UL></FORM>
<P>
<HR>

<P><!******************END EXAMPLE*****************>
<P>
<P><B><FONT color=3D#aa00dd size=3D+1>Q </FONT></B>In <A=20
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/conta=
nddiff.html">Part=20
A</A> we discussed continuity, and here we discussed differentiability. =
Are all=20
continuous functions differentiable? Are all differentiable functions=20
continuous? <BR><B><FONT color=3D#aa00dd size=3D+1>A </FONT></B>Briefly: =
<BR>(a) Not=20
all continuous functions are differentiable. For instacne, the =
closed-form=20
function f(x) =3D |x| is continuous at every real number (including x =
=3D 0), but=20
not differentiable at x =3D 0.<BR>(b) However, every differentiable =
function is=20
continuous. More precisely, we have the following theorem.=20
<P><SUB><IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/exiconw.gif"=
></SUB><FONT=20
color=3D#330033 size=3D4><B> Theorem </B><I>Differentiability Implies=20
Continuity</I></FONT>=20
<P>If f is differentiable at a, then it is continuous at a.=20
<P><FONT color=3D#330033 size=3D4><B>Proof</B></FONT> <BR>Suppose that f =
is=20
differentiable at the point x =3D a. Then we know that=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>f(a+h) <FONT face=3DCourier>-</FONT> f(a)<BR><IMG =
height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D60><BR>h</CENTER></TD>
      <TD>exists, and equals f<FONT=20
  face=3DCourier>'</FONT>(a).</TD></TR></TBODY></TABLE></UL>Thus,=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD>f(a+h) <FONT face=3DCourier>-</FONT> f(a)</TD>
      <TD>=3D</TD>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD vAlign=3Dtop>
        <CENTER>f(a+h) <FONT face=3DCourier>-</FONT> f(a)<BR><IMG =
height=3D1=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/F=
R.GIF"=20
        width=3D60><BR>h</CENTER></TD>
      <TD vAlign=3Dtop><SUP>.</SUP> h</TD>
      <TD>=3D</TD>
      <TD>f<FONT face=3DCourier>'</FONT>(a)<SUP>.</SUP> 0 =3D 0.</TD>
      <TD>&nbsp; &nbsp; <FONT color=3D#aa00dd>Limit of product =3D =
product of=20
        limits</FONT></TD></TR></TBODY></TABLE></UL>This gives=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD>f(a+h)</TD>
      <TD>=3D</TD>
      <TD align=3Dmiddle>lim<BR>h<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD>[f(a+h) <FONT face=3DCourier>-</FONT> f(a)] + f(a)</TD>
      <TD>=3D</TD>
      <TD>0 + f(a) =3D f(a).</TD>
      <TD>&nbsp; &nbsp; <FONT color=3D#aa00dd>Limit of sum =3D sum of=20
      limits</FONT></TD></TR></TBODY></TABLE></UL>If we take x to be =
a+h, then h =3D=20
x<FONT face=3DCourier>-</FONT>a, and the above result can be written as=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>x<FONT face=3DCourier>-</FONT>a<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">0</TD>
      <TD>f(x)</TD>
      <TD>=3D</TD>
      <TD>f(a).</TD></TR></TBODY></TABLE></UL>In other words,=20
<UL>
  <TABLE>
    <TBODY>
    <TR>
      <TD align=3Dmiddle>lim<BR>x<IMG=20
        =
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/SYMB/R=
AR.GIF">a</TD>
      <TD>f(x)</TD>
      <TD>=3D</TD>
      <TD>f(a),</TD></TR></TBODY></TABLE></UL>which means that f is =
continuous at x =3D=20
a. You can now either go on and try the rest of the exericses in the <A=20
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/candd=
ex.html">exercise=20
set for this topic</A>. <BR>&nbsp; <! *** Links Here>
<P>
<CENTER><IMG=20
src=3D"http://people.hofstra.edu/Stefan_Waner/realworld/elts/pinkline.gif=
"></CENTER>
<P>
<CENTER>
<TABLE>
  <TBODY>
  <TR>
    <TD><A =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/index.html"=20
      target=3D_top><FONT face=3D"arial, helvetica, sans-serif" =
color=3D#550000=20
      size=3D2><B>Return to Main Page</FONT></A> <BR><A=20
      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/conta=
nddiff.html"><FONT=20
      face=3D"arial, helvetica, sans-serif" color=3D#ff0000 =
size=3D2><B>Part A:=20
      Continuity</FONT></B></A> <BR><A=20
      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/calctopic1/candd=
ex.html"><FONT=20
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href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/textindex.html">=
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ONT=20
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href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/tcfinitep.html">=
<FONT=20
      face=3D"arial, helvetica, sans-serif" color=3Dcrimson =
size=3D2><B>Everything for=20
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      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/tccombop.html"><=
FONT=20
      face=3D"arial, helvetica, sans-serif" color=3Dblue =
size=3D2><B>Everything for=20
      Finite Math &amp; Calculus</B></FONT></A> <BR><A=20
      =
href=3D"http://people.hofstra.edu/Stefan_Waner/realworld/functions/func.h=
tml"=20
      target=3D_blank><FONT face=3D"times, times new roman" =
color=3Dtomato><B>Utility:=20
      </B></FONT><FONT face=3D"arial, helvetica, sans-serif" =
color=3D#550000=20
      size=3D2><B>Function Evaluator &amp; Grapher</B></FONT></A>=20
  </B></TD></TR></TBODY></TABLE></CENTER>
<P>
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<CENTER>Last Updated:<I>October, 1999</I></CENTER>
<CENTER>Copyright =A9 1999 StefanWaner and Steven R. Costenoble=20
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